Target gravity

[BDawg]

For 75% efficiency and pppg's of 1.036, 1.034, and 1.028 for the 2-row, C40, and roasted barley, respectively, in 4.5 gallons I get 1.056.

8x36=288
1x34=34
0.5x28=14

288+34+14=336

336/4.5=74.67

74.67x0.75=56

You happen to have a link or can you explain that math for me? Like I said, I'm a software dude. Interested in the calculation though.

First, multiply the weight of each grain by its pppg to get the contribution of each grain:

8x36=288
1x34=34
0.5x28=14

Next, add them up to get the theoretical points in a perfect 100% extraction:
288+34+14=336

Next, divide by the batch size so you know how many points per gallon you'll get:
336/4.5=74.67

finally, multiply by the efficiency so that it adjusts for everyone's less than perfect extraction:
74.67x0.75=56

move the "56" over to 1.056, and you are done.

Hope this makes sense.

[Dirk McLargeHuge]

For 75% efficiency and pppg's of 1.036, 1.034, and 1.028 for the 2-row, C40, and roasted barley, respectively, in 4.5 gallons I get 1.056.

8x36=288
1x34=34
0.5x28=14

288+34+14=336

336/4.5=74.67

74.67x0.75=56

You happen to have a link or can you explain that math for me? Like I said, I'm a software dude. Interested in the calculation though.

First, multiply the weight of each grain by its pppg to get the contribution of each grain:

8x36=288
1x34=34
0.5x28=14

Next, add them up to get the theoretical points in a perfect 100% extraction:
288+34+14=336

Next, divide by the batch size so you know how many points per gallon you'll get:
336/4.5=74.67

finally, multiply by the efficiency so that it adjusts for everyone's less than perfect extraction:
74.67x0.75=56

move the "56" over to 1.056, and you are done.

Hope this makes sense.

[DeepEllumBrews]

For 75% efficiency and pppg's of 1.036, 1.034, and 1.028 for the 2-row, C40, and roasted barley, respectively, in 4.5 gallons I get 1.056.

8x36=288
1x34=34
0.5x28=14

288+34+14=336

336/4.5=74.67

74.67x0.75=56

You happen to have a link or can you explain that math for me? Like I said, I'm a software dude. Interested in the calculation though.

First, multiply the weight of each grain by its pppg to get the contribution of each grain:

8x36=288
1x34=34
0.5x28=14

Next, add them up to get the theoretical points in a perfect 100% extraction:
288+34+14=336

Next, divide by the batch size so you know how many points per gallon you'll get:
336/4.5=74.67

finally, multiply by the efficiency so that it adjusts for everyone's less than perfect extraction:
74.67x0.75=56

move the "56" over to 1.056, and you are done.

Hope this makes sense.

Perfect! Thanks a lot man!

Now can you guys explain why duders LHBS guy thought it would be so high. Also, I run consistently at 80% efficiency and I figured it was low as well. Just confused is all. Thanks again for spelling it out BDawg, I appreciate it.

[Dmp]

Ya, looks like I need to start doing smaller worts so I can start getting some punch you in the face beers...

[BDawg]

No idea why he would think it would be so high, unless he was so used to giving calcs for LME & DME that he forgot to adjust.


Here's a trick for roughly estimating OG (makes for fast proofs on the BJCP exam... hint hint):

At 70% efficiency, a 36pppg grain (which is most base malts) will give you 25pppg.
so, that means in a 5 gallon batch, you get 10 pts for every 2 lbs of grain.

1.030 => 6 lbs of grain
1.040 => 8 lbs of grain
1.050 => 10 lbs of grain
1.060 => 12 lbs of grain
1.070 => 14 lbs of grain
1.080 => 16 lbs of grain
1.090 => 18 lbs of grain
1.100 => 20 lbs of grain

You can pretty much estimate this in your head on the fly and come out pretty close.

HTH-

[Dmp]

No idea why he would think it would be so high, unless he was so used to giving calcs for LME & DME that he forgot to adjust.


Here's a trick for roughly estimating OG (makes for fast proofs on the BJCP exam... hint hint):

At 70% efficiency, a 36pppg grain (which is most base malts) will give you 25pppg.
so, that means in a 5 gallon batch, you get 10 pts for every 2 lbs of grain.

1.030 => 6 lbs of grain
1.040 => 8 lbs of grain
1.050 => 10 lbs of grain
1.060 => 12 lbs of grain
1.070 => 14 lbs of grain
1.080 => 16 lbs of grain
1.090 => 18 lbs of grain
1.100 => 20 lbs of grain

You can pretty much estimate this in your head on the fly and come out pretty close.

HTH-

so how do i get 20 lbs of grain in a mash ton that is a igloo container? double mash!?

[Dmp]

No idea why he would think it would be so high, unless he was so used to giving calcs for LME & DME that he forgot to adjust.


Here's a trick for roughly estimating OG (makes for fast proofs on the BJCP exam... hint hint):

At 70% efficiency, a 36pppg grain (which is most base malts) will give you 25pppg.
so, that means in a 5 gallon batch, you get 10 pts for every 2 lbs of grain.

1.030 => 6 lbs of grain
1.040 => 8 lbs of grain
1.050 => 10 lbs of grain
1.060 => 12 lbs of grain
1.070 => 14 lbs of grain
1.080 => 16 lbs of grain
1.090 => 18 lbs of grain
1.100 => 20 lbs of grain

You can pretty much estimate this in your head on the fly and come out pretty close.

HTH-

so how do i get 20 lbs of grain in a mash ton that is a igloo container? double mash!?

or think about adding extract at the boil....

[Dirk McLargeHuge]

No idea why he would think it would be so high, unless he was so used to giving calcs for LME & DME that he forgot to adjust.


Here's a trick for roughly estimating OG (makes for fast proofs on the BJCP exam... hint hint):

At 70% efficiency, a 36pppg grain (which is most base malts) will give you 25pppg.
so, that means in a 5 gallon batch, you get 10 pts for every 2 lbs of grain.

1.030 => 6 lbs of grain
1.040 => 8 lbs of grain
1.050 => 10 lbs of grain
1.060 => 12 lbs of grain
1.070 => 14 lbs of grain
1.080 => 16 lbs of grain
1.090 => 18 lbs of grain
1.100 => 20 lbs of grain

You can pretty much estimate this in your head on the fly and come out pretty close.

HTH-

Nice tip. Thanks, BDawg. That will help when I'm at work with nothing to help me.

Now I have to make room for it in my brain. Lose mom's birthday or how to drive? Still working on it.