So, I have a recipe that calls for 12.75 lbs of grain. I want to maximize the grain portion and minimize the extract (liquid) portion. The base malts are 9lb Belgian Pils and 3lb German Wheat. The amount I can fit also varies on the grain to water ratio in the wort which I usually do about 1.25 to 1.5 lb per quart (if I remember right).
Given all this fancy pants math, I come up with this:
The full recipe calls for 12.75 * 1.25 quarts of water about 16q = 4g.
However, I'm thinking that 12.75 lb of grain has more volume than 1g which means I can't fit it all in the Igloo.
My best guess is this for the recipe:
- .75 specialty grains in the mash (unchanged)
6 lbs belgian pils malt (grain)
2 lbs german wheat malt (grain)
Liquid malt substitute for 3 lbs belgian malt (added during boil)
Liquid malt substitute for 1 lb wheat malt (added during boil)
This reduces my volume by about 1.25 gallons for liquid only and also reduces the volume of 4 lbs of grain.
Anyway, if there's a short answer, what's the approximate volume of 1lb of crushed grain?



